the lcm and hcf of two numbers is 4 and 560 respectively if the first number is 28 find the other number
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let the other number be x
LCM X HCF = 28 x
![4 \times 560 = 28 \times x \\ x = \frac{4 \times 560}{28} \\ x = 4 \times 20 \\ x = 80 4 \times 560 = 28 \times x \\ x = \frac{4 \times 560}{28} \\ x = 4 \times 20 \\ x = 80](https://tex.z-dn.net/?f=4+%5Ctimes+560+%3D+28+%5Ctimes+x+%5C%5C+x+%3D++%5Cfrac%7B4+%5Ctimes+560%7D%7B28%7D++%5C%5C+x+%3D+4+%5Ctimes+20+%5C%5C+x+%3D+80)
LCM X HCF = 28 x
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