the lcm and hcf of two polynomial p(x) and q(x) are 36x^3(x+a) (x^3 - a^3) and x^2(x-a), respectively , if p(x) =4x(x^2-a^2), then the what is the value of q(x)
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Thanks ☺️ a lot.........
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Answer:
q(x)= 27x(x³-a³)
Step-by-step explanation:
If a and b are two numbers ,then
Product of (a,b) = LCM (a,b) * HCF (a,b)
This is, (a*b) = LCM (a,b) * HCF (a,b)
Here,
p(x) * q(x) = LCM {p(x),q(x)} * {HCF p(x),q(x)}
So,
q(x) = LCM {p(x),q(x)} * {HCF p(x),q(x)} / p(x)
= {36*3(x+a)(x³-a³) × x²(x-a)} / 4x(x²-a²)
= 108(x³-a³)* x²* (x+a)(x-a) / 4x (x²-a²)
= 108(x³-a³)* x²* (x²-a²) / 4x (x²-a²)
= 27x(x³-a³)- ANSWER
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