Math, asked by royr80216, 9 months ago

the lcm and hcf of two polynomial p(x) and q(x) are 36x^3(x+a) (x^3 - a^3) and x^2(x-a), respectively , if p(x) =4x(x^2-a^2), then the what is the value of q(x)​

Answers

Answered by samhitamoharir
0

Answer:

Thanks ☺️ a lot.........

Answered by footballchampionaqil
0

Answer:

q(x)= 27x(x³-a³)

Step-by-step explanation:

If a and b are two numbers ,then

Product of (a,b) = LCM (a,b) * HCF (a,b)

This is, (a*b) = LCM (a,b) * HCF (a,b)

Here,

p(x) * q(x) = LCM {p(x),q(x)} * {HCF p(x),q(x)}

So,

q(x) = LCM {p(x),q(x)} * {HCF p(x),q(x)} / p(x)

= {36*3(x+a)(x³-a³) × x²(x-a)} / 4x(x²-a²)

= 108(x³-a³)* x²* (x+a)(x-a) / 4x (x²-a²)

= 108(x³-a³)* x²* (x²-a²) / 4x (x²-a²)

= 27x(x³-a³)- ANSWER

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