Question

The LCM and HCF of two polynomials () () are ( 4 + ) 4( 2 − + 1) respectively. If  () = 28( 2+ 1), ().​

Answer 1

Step-by-step explanation:

Correct option is

C

3(x−1)(x−2)

Given:

p(x)=?

q(x)=4(x+2)(x+3)

L.C.M =12(x

2

−4)=12(x+2)(x−2)

So, H.C.F = (x−1)(x+3)

Using the formula,

p(x)×q(x)= H.C.F × L.C.M

p(x)=

4(x+2)(x+3)

12(x+2)(x−2)(x−1)(x+3)

=3(x−1)(x−2)

Therefore, p(x) is 3(x−1)(x−2).

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