The lcm of 2 number of 3 digit each 1740 and hcf is 290 then two number are
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The numbers are 580 and 870.
Step-by-step explanation:
Given LCM of two numbers is 1740 and HCF is 290.
The product of two numbers = LCM x HCF = 1740 x 290 = 504600
The numbers must be multiples of HCF. So, let the numbers be 290a and 290b where a and b are two numbers prime to each other.
290a x 290b = 504600
=> ab = 6
Now, the pairs of numbers whose product is 6 are (1, 6) and (2, 3)
Required numbers are 1 x 290 = 290 and 6 x 290 = 1740
2 x 290 = 580 and 3 x 290 = 870
Given that both the numbers are 3 digits so answer cannot be 290 and 1740.
Hence, the numbers are 580 and 870.
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