Question

The LCm of 2 numbers 1260 their lcm is

Answer 1

Answer:

Let a is the LCM and b is the HCF of two numbers.

Given, a + b = 1260 ..............1

and a = b + 900 ...............2

Put value of a in equation 1, we get

b + 900 + b = 1260

=> 2b + 900 = 1260

=> 2b = 1260 - 900

=> 2b = 360

=> b = 360/2

=> b = 180

From equation 1, we get

a + 180 = 1260

=> a = 1260 - 180

=> a = 1080

So, LCM = a = 1080

and HCF = b = 180

Now, product of two numbers = LCM * HCF

=> product of two numbers = 1080 * 180

=> product of two numbers = 194400

Answer 2

Step-by-step explanation:

Let a is the LCM and b is the HCF of two numbers.

Given, a + b = 1260 ..............1

and a = b + 900 ...............2

Put value of a in equation 1, we get

b + 900 + b = 1260

=> 2b + 900 = 1260

=> 2b = 1260 - 900

=> 2b = 360

=> b = 360/2

=> b = 180

From equation 1, we get

a + 180 = 1260

=> a = 1260 - 180

=> a = 1080

So, LCM = a = 1080

and HCF = b = 180

Now, product of two numbers = LCM * HCF

=> product of two numbers = 1080 * 180

=> product of two numbers = 194400