The LCM of 2 numbers is 495 and the HCF of
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Answer:
Let one number =x Then other number =100−x
LCM =495 and HCF=5
Product of number =HCF×LCM
∴x(100−x)=495×5
⇒100x−x
2
=2475
⇒x
2
−100x+2475=0
⇒x
2
−45x−55x+2475=0
⇒x(x−45)−55(x−45)=0
⇒(x−45)(x−55)=0
⇒x=45 or 55
∴ The one numbers is 45, then another number =100−45=55 or
if one number is 55, then another number =100−55=45
∴ Required difference =55−45=10
Step-by-step explanation:
The LCM of two numbers is 495 and their HCF is 5. If the sum of the numbers is 100 then their difference is:
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