The lcm of 2x,5x,7x is ________ , where x is a positive integer
Answers
Answer:
70x
Step-by-step explanation:
2x;5x;7x
(2;5;7)x
(1;5;7)2x
(1;1;7)10x
(1;1;1)70x
Given : The algebraic terms are 2x, 5x and 7x
To find : Their LCM.
Solution :
We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the required LCM)
In this case, we will be separately calculating the LCM of numerical parts and LCM of algebraic constants. At last, we will multiply their two LCM(s).
Numerical parts are = 2,5,7
So, all of them are prime numbers (which are only divisible by 1 and themselves). That's why, their LCM will be their product.
So, LCM of 2,5,7 is = 2 × 5 × 7 = 70
And,
Algebraic constants are = x,x,x
So, LCM of x,x,x is = x
(As, all of them are equal, their LCM will be the constant itself.)
So, the final LCM will be :
= 70 × x
= 70x
(This will be considered as the final result.)
Hence, the LCM of 2x,5x,7x is 70x