Question

The lcm of 36,56 and n is 1512.what is the smallest value of n?

Answer 1

The LCM is made up of the smallest possible number of the prime factors of the numbers.

36=2×2×3×3

56=2×2×2×7

LCM=2×2×2×3×3×3×7

Therefore, n=3×3×3

2×2×2 is required, but this is accounted for in 56.

3×3×3 is required, but does not appear in

36 or in 56

So the smallest value of p is 27=3×3×3

Answer 2

Step-by-step explanation:

hi here is your answer

The LCM is made up of the smallest possible number of the prime factors of the numbers.

36=2*2*3*3

56=2*2*2*x*7

LCM=2*2*2*3*3*3*7

∴

n=3*3*3

2*2*2 is required, but this is accounted for in

56

3*3*3 is required, but does not appear in

36 or in 56

So the smallest value of

n is 27=3*3*3

thank you✌