The LCM of (a + b) and (a - b) is:
a) (a + b) (a + b)(a - b)
b) (a + b) (a? +b?) (a + b)
c) (a + b )(a + b + ab) (a + b)
d) (a + b°) (a - b) (a - b)
Answers
Answered by
47
By the rule of algebra,
a^2 - b^2 = (a+b) (a-b)
So, the LCM of (a+b) and (a-b) is (a^2 - b^2)
Hope you have understood
Thanks
Answered by
0
Answer:
the answer is c
Step-by-step explanation:
a + b [a + b +ab] [a + b }
i hope it helps
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