Question

THE LCM OF A NUMBER IS 21 AND THE HCF IS 1 .
IF ONE NUMBER IS 3 THEN FIND THE OTHER NUMBER ​

Answer 1

Answer:

LCM=21

HCF=1

LCM×HCF=Product of the two numbers

21×1=3×y

21=3×y

7=y

So the another number is 7

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Answer 2

Answer:

There is formula introduced in LCM&HCF concept.

LCM×HCF=product of two numbers.

Symbollycally written as LCM×HCF=a×b.

Here a and b are two numbers given in question.

According to this question,

*LCM=21

*HCF=1

*a=3

*b=?

We know the formula that LCM×HCF=a×b.

*21×1=3×b

*21=3×b

Therefore b=21÷3 i.e, b=7.

Hence required number in this question is 7.