Question

The LCM of four number is 180. find the product of the four numbers if the HCF of each pair is 3
(a)14580
(b)4860
(c)1620
(d)540​

Answer 1

(b) 4860 is the right answer

Let the 4 no.s be 3a,3b,3c,3d

LCM = abcd x HCF

=> abcd = 180/3

= 60

Therefore, product of the no.s = 3a x 3b x 3c x 3d

= 3⁴ x 60

= 4860

Answer 2

Given:

LCM of four number is 180

HCF of each pair is 3

The correct option is "b"

Here Since the HCF of each pair =3

let the four numbers be 3a,3b,3c,3d

LCM=abcd × HCF

LCM/HCF= abcd

=180/3

=60

Product of the numbers =3a×3b×3c×3d

$=3^{4}*60$

=81 × 60

=4860

Hence the product of the four numbers is 4860