Question

the LCM of polynomials 14(x^2 -1)(x^2 +1) and 18(x^4 -1)(x +1) is​

Answer 1

Answer:

The final answer is $126(x+1)(x^4-1)$

Step-by-step explanation:

Given,

We have an equation $14(x^2 -1)(x^2 +1)$ and $18(x^4 -1)(x +1)$. We need to find the LCM of the two equations. LCM is the least common multiple, It is the least number which is divisible by two numbers. To find the Least Common Multiple of the two number, We first take the common numbers out of it and multiply it with two numbers until they are equal.

Here we have two equations $18(x^4 -1)(x +1)$ and $14(x^2 -1)(x^2 +1)$. The common terms are $2(x^4-1)$ since $(x^2-1)(x^2+1)=x^4-1$.

We now have terms $9(x+1)$ and 7. Multiplying first equation with 7 and second with 9(x+1) we get,$63(x+1)$.

The LCM will be$126(x+1)(x^4-1)$.

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