The LCM of the two numbers is 126 and their HCF is 21.If the one of the two number is 63,What is the other number?
Answers
If the lowest common multiple of 2 numbers is 126, and they share 6 as the highest common factor, I’m going to start by suggesting that 126×1=126, and 126÷6=21.
If the lowest common multiple of 2 numbers is 126, and they share 6 as the highest common factor, I’m going to start by suggesting that 126×1=126, and 126÷6=21.If you then say one of the numbers is 18, 18 needs to be a factor of 126: 7×18=126.
If the lowest common multiple of 2 numbers is 126, and they share 6 as the highest common factor, I’m going to start by suggesting that 126×1=126, and 126÷6=21.If you then say one of the numbers is 18, 18 needs to be a factor of 126: 7×18=126.18 is also a factor of 18: 18×1=18.
If the lowest common multiple of 2 numbers is 126, and they share 6 as the highest common factor, I’m going to start by suggesting that 126×1=126, and 126÷6=21.If you then say one of the numbers is 18, 18 needs to be a factor of 126: 7×18=126.18 is also a factor of 18: 18×1=18.So 126 won’t be the other number here, because then 6 wouldn’t be the HCF.
If the lowest common multiple of 2 numbers is 126, and they share 6 as the highest common factor, I’m going to start by suggesting that 126×1=126, and 126÷6=21.If you then say one of the numbers is 18, 18 needs to be a factor of 126: 7×18=126.18 is also a factor of 18: 18×1=18.So 126 won’t be the other number here, because then 6 wouldn’t be the HCF.126÷2=63, not divisible by 6.
If the lowest common multiple of 2 numbers is 126, and they share 6 as the highest common factor, I’m going to start by suggesting that 126×1=126, and 126÷6=21.If you then say one of the numbers is 18, 18 needs to be a factor of 126: 7×18=126.18 is also a factor of 18: 18×1=18.So 126 won’t be the other number here, because then 6 wouldn’t be the HCF.126÷2=63, not divisible by 6.126÷3=42, divisible by 6: 6×7=42
If the lowest common multiple of 2 numbers is 126, and they share 6 as the highest common factor, I’m going to start by suggesting that 126×1=126, and 126÷6=21.If you then say one of the numbers is 18, 18 needs to be a factor of 126: 7×18=126.18 is also a factor of 18: 18×1=18.So 126 won’t be the other number here, because then 6 wouldn’t be the HCF.126÷2=63, not divisible by 6.126÷3=42, divisible by 6: 6×7=42No multiple of 42 is divisible by 18 until we reach 126.
If the lowest common multiple of 2 numbers is 126, and they share 6 as the highest common factor, I’m going to start by suggesting that 126×1=126, and 126÷6=21.If you then say one of the numbers is 18, 18 needs to be a factor of 126: 7×18=126.18 is also a factor of 18: 18×1=18.So 126 won’t be the other number here, because then 6 wouldn’t be the HCF.126÷2=63, not divisible by 6.126÷3=42, divisible by 6: 6×7=42No multiple of 42 is divisible by 18 until we reach 126.The other number is 42.
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