Math, asked by kaverimediboina, 4 months ago

The LCM of three different numbers is 2048. Which one of the following can never be there HCF?

Answers

Answered by rashidixit1209
1

Answer:

The LCM of three different number is 1024. 1024 should be divisible by all the given number, if any (as u didn't mentioned options here) number which is not dividing 1024 that can never be there HCF

Answered by pruthaasl
0

Complete question:

The LCM of three different numbers is 2048. Which one of the following can never be there HCF?

Options:

a) 8

b) 124

c) 32

d) 256

Answer:

b) 124 can never be the HCF.

Step-by-step explanation:

We know that the LCM must be a multiple of HCF. Therefore,

  1. 2048 ÷ 8 = 256
  2. 2048 ÷ 124 = 512/31
  3. 2048 ÷ 32 = 64
  4. 2048 ÷ 256 = 8

As we can see, 8, 32, and 256 divide the LCM 2048 completely. Hence, 8, 32, and 256 can be the HCF of the three numbers.

Since 124 does not divide 2048 completely, it is not a multiple of 2048.

Therefore, 124 cannot be the HCF of the three numbers.

#SPJ3

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