Question

The lcm of three numbers is 4752 and hcf is 6. if two munbers are 48 and 66 find third number

Answer 1

The HCF is given as 6, so

Let the third number be 6a

So, writing the 3 numbers as =

48 = 2⁴ x 3

66 = 2 x 3 x 11

6x = 2 x 3 x a

Now LCM is given 4752

4752 = 2⁴ x 3 x 11 x a

a = 4752 / 528

a = 9

So, our third number is 6(9)

= 54

Answer 2

Thank you sir

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