Question

The lcm of three numbers is 4752 and their hcf is 6 if two numbers are 48 and 66 find the third number

Answer 1

Let's assume that the Number be A
we have an identity
HCF X LCM = Product of the numbers
6 X 4752 = 48x66xA
A=(6X 4752)/(48x66)

A = 9

Answer 2

$<b><u><i>$Refer to the attachment ,

$<b><u><i>$Using the formula LCM × HCF = Product of the numbers we will get the value of A = 9