The LCM of two is 2079and their HCF is 27 if one number is 297 find other
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Answered by
1
LCM×HCF=ORODUCT OF NO.
2079×27=297×X
X=189
2079×27=297×X
X=189
Answered by
1
Hi ,
Let a and b are two numbers and their LCM = l and HCF = h then
ab = lh
a = 297 ,
b = ?
l = 2079
h = 27
297 × b = 2079 × 27
b = ( 2079 × 27 ) / 297
b = 189
I hope this helps you.
:)
Let a and b are two numbers and their LCM = l and HCF = h then
ab = lh
a = 297 ,
b = ?
l = 2079
h = 27
297 × b = 2079 × 27
b = ( 2079 × 27 ) / 297
b = 189
I hope this helps you.
:)
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