the LCM of two number is 2079 and their HCF is 27 if one of the number is 189 find the other number
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LCM * HCF = N1 * N2
2079 * 27 = 189 * N2
N2 = 2079 * 27 / 189
N2 = 297
2079 * 27 = 189 * N2
N2 = 2079 * 27 / 189
N2 = 297
purvisri02:
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given lcm of 2 numbers is 2079
and hcf of the 2 numbers is 27
their is a rule as
lcm=(product of numbers )/hcf
given one number as 189
let the other number be x
therefore , 2079=189x/27
on solving x= (2079*27)/189
we get x= 297 which is the answer
and hcf of the 2 numbers is 27
their is a rule as
lcm=(product of numbers )/hcf
given one number as 189
let the other number be x
therefore , 2079=189x/27
on solving x= (2079*27)/189
we get x= 297 which is the answer
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