Question

The LCM of two number is 4080 and their HCF is 13 6 if one of the numbers is 680 find the other number

Answer 1

Answer:

The prime factorization of the HCF:

160=2*2*2*2*2*5

The prime factorization of the LCM:

4800=2*2*2*2*2*3*3*5*5

The HCF must have factors that are in both numbers.

The LCM must have factors that are in one or both of the numbers.

160: 2*2*2*2*2* 5

LCM: 2*2*2*2*2*3*3*5*5

GCF: 2*2*2*2*2* 5

Therefore, the other number needs to be 4800.

Answer: 4800 is the other number

Answer 2

Answer:

we know that LCM(x,y) × HCF(x,y)= x×y

let the other no. be y

4080 × 136 = 680 × y

4080 × 136/680 = y

816= y