Question

The lcm of two number is 4080 and their hcf is 136. If one number is 680,find the other.

Answer 1

SOLUTION:-

Given:

⚫LCM= 4080

⚫HCF= 136

Therefore,

We know that, product of two numbers;

=) Product of their LCM & HCF.

⚫One number= 680

⚫Let other number be x

⚫Product of no.=product of LCM&HCF

$= > 680x = 4080 \times 136 \\ \\ = > x = \frac{4080 \times 136}{680} \\ \\ = > x = \frac{408 \times 136}{68} \\ \\ = > x = 6 \times 136 \\ \\ = > x = 816$

Thus,

The other number is 816.

Hope it helps ☺️

Answer 2

Answer:

816

Step-by-step explanation:

SOLUTION:-

Given:

⚫LCM= 4080

⚫HCF= 136

Therefore,

We know that, product of two numbers;

=) Product of their LCM & HCF.

⚫One number= 680

⚫Let other number be x

⚫Product of no.=product of LCM&HCF

\begin{gathered}= > 680x = 4080 \times 136 \\ \\ = > x = \frac{4080 \times 136}{680} \\ \\ = > x = \frac{408 \times 136}{68} \\ \\ = > x = 6 \times 136 \\ \\ = > x = 816\end{gathered}

=>680x=4080×136

=>x=

680

4080×136

=>x=

68

408×136

=>x=6×136

=>x=816