Math, asked by chatan3349, 11 months ago

The lcm of two number is 51 times their hcf.if one number is 27.find the other number?

Answers

Answered by rajivbista338
0

Answer:

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Answered by Smarth39
0

Answer:

Step-by-step explanation:

Answer:

153

Step-by-step explanation:

We can list down the prime factors of 27.

The prime factors of 27 are as follows:

27 = 3 × 3 × 3

The prime factors of 51 are as follows:

51 = 3 × 17

The other number must be a multiple of 17 and 3 since 17 is also prime number.

The number should be however more than 51.

27 is divisible by : 3,  9  ,  27

The lcm could therefore be :

51 × 3 = 153

51 × 9 = 459

51 × 27 = 1377

Since 153 is not divisible by 27 we eliminate it and take 459.

The HCF is 9 and the other number is 153 since 459 is divisible by 27 and 153.

The other number is thus 153 and the HCF is 9.

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