The LCM of two number is 96 and their HCF is 8 . If one of the number is 32 , find the other number
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Answered by
5
lcm(a,b)= 96
hcf(a,b)=8
a=32
hcf(a,b)×lcm(a,b)=a×b
8×96=32×b
b=8×96÷32
b=24
hcf(a,b)=8
a=32
hcf(a,b)×lcm(a,b)=a×b
8×96=32×b
b=8×96÷32
b=24
Answered by
6
Answer:
Hey friend,
Here is the answer you are searching for
Given,
L.C.M = 96
H.C.F = 8
One number = 32
Let another number be x,
By using the formula,
H.C.F × L.C.M = Product of both numbers.
x = 96×8/32 = 96/4 = 24
Therefore,
Other number = 24.
HOPE IT HELPS YOU.
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