The LCM of two number S is 14 times their HCF the sum of LCM and HCF is 600 if one number is 280 then find the other number
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the 2nd no is 80 it is the solution of this qestion
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LCM=14x
HCF=x
LCM+HCF=600
one number=280
14x+x=600
15x=600
x=600÷15
x=40
HCF=40
LCM=14×x
14×40=560
HCF×LCM=product of two numbers
40×560=280×y
y=280÷40×560
y=80
I hope it will help you
HCF=x
LCM+HCF=600
one number=280
14x+x=600
15x=600
x=600÷15
x=40
HCF=40
LCM=14×x
14×40=560
HCF×LCM=product of two numbers
40×560=280×y
y=280÷40×560
y=80
I hope it will help you
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