The LCM of two numbers a and b is 24 and their HCF is 1 then find those two numbers
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we know,
product of two numbers=LCM*HCF
given lcm=24
hcf=1
numbers are a and b
=>ab= 24*1=24
ab=24
possible values of a and b such that a*b=24 :
(1,24) ; (2,12) ; (3,8) ; (4,6) ; (6,4) ; (8,3) ; (12,2) ; (1,24)
we get 8 set of numbers
when we find the hcf of each of the set of numbers, we observe that the hcf of 4 sets of numbers i.e., of (1,24) ; (3,8) ; (24,1) ; (8,3) is 1
when we find lcm of the 4 sets individually we find that lcm of all the four sets is 24
so, the numbers are either 1 and 24 or 3 and 8
where if a takes one of the value then b takes another value
product of two numbers=LCM*HCF
given lcm=24
hcf=1
numbers are a and b
=>ab= 24*1=24
ab=24
possible values of a and b such that a*b=24 :
(1,24) ; (2,12) ; (3,8) ; (4,6) ; (6,4) ; (8,3) ; (12,2) ; (1,24)
we get 8 set of numbers
when we find the hcf of each of the set of numbers, we observe that the hcf of 4 sets of numbers i.e., of (1,24) ; (3,8) ; (24,1) ; (8,3) is 1
when we find lcm of the 4 sets individually we find that lcm of all the four sets is 24
so, the numbers are either 1 and 24 or 3 and 8
where if a takes one of the value then b takes another value
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