Question

The LCM of two numbers is 12 times their HCF. The sum of HCF and LCM is 403. If one of the numbers is 93. then the other number is (a) 124 (b) 128 (c) 134 (d) 138​

Answer 1

Answer:

Correct option is

A

124

Let the HCF =x

According to the question LCM=12x

x+12x=403

13x=403⇒x=31

∴HCF=31andLCM=12×31=372

Let the second number =y

Productofnumbers=HCF×LCM

93×y=31×372

y=31×372/93

y=124

Hence the second number is 124