the LCM of two numbers is 128 and their product of 8192. find their HCF. solve
Answers
Answered by
60
Hey
Here is your answer,
Product of two numbers = HCF x LCM
8192 = 128 x HCF
HCF = 8192/128
HCF = 64.
Hope it helps you!
Here is your answer,
Product of two numbers = HCF x LCM
8192 = 128 x HCF
HCF = 8192/128
HCF = 64.
Hope it helps you!
Answered by
1
Concept:
Mathematical expression is a mathematical relation or statement or term involves various mathematical quantities, numbers, mathematical operations, variable and other mathematical components etc.
From mathematical Identities we know that,
Product of two numbers = (LCM of numbers)*(HCF of numbers)
Given:
Given that the LCM of two numbers is 128 and their product of 8192.
Find:
The value of the HCF of that two numbers.
Solution:
Given that, the product of two numbers is 8192
and the LCM of the number is 128
Let the HCF be x.
According to mathematical identity,
128*x = 8192
x = 8192/128
x = 64
Hence the HCF of that two numbers whose LCM is 128 and product is 8192 is given by 64.
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