The lcm of two numbers is 14 times their hcf. the sum of lcm and hcf is 600. if one number is 280,then find other number
Answers
Answered by
2633
GIVEN: HCF+LCM= 600, ONE NUMBER= 280
Let the HCF= X
LCM= 14X
HCF+LCM= 600
X+ 14X=600
15X= 600
X= 600/15
X= 40
HCF= 40
LCM = 14X= 14× 40= 560
HCF×LCM= 1ST NUMBER × 2ND NUMBER
40× 560= 280× 2ND NUMBER
2ND NUMBER= (40×560) /280
2ND NUMBER= 40×2
2ND NUMBER= 80
Hope this will help you....
Let the HCF= X
LCM= 14X
HCF+LCM= 600
X+ 14X=600
15X= 600
X= 600/15
X= 40
HCF= 40
LCM = 14X= 14× 40= 560
HCF×LCM= 1ST NUMBER × 2ND NUMBER
40× 560= 280× 2ND NUMBER
2ND NUMBER= (40×560) /280
2ND NUMBER= 40×2
2ND NUMBER= 80
Hope this will help you....
Answered by
527
HI...
GIVEN:-
ONE NO. IS 280
LET HCF BE X
so LCM = 14X
SUM OF HCF AND LCM = 600
X + 14X = 600
15X = 600
SO HCF = 40
LCM = 14×40 => 560
TO FIND OTHER NO. :-
first no. = 280
second no. = y
WE KNOW THAT
40 × 560 = 280 × y
22400 = 280y
y = 22400/280
GIVEN:-
ONE NO. IS 280
LET HCF BE X
so LCM = 14X
SUM OF HCF AND LCM = 600
X + 14X = 600
15X = 600
SO HCF = 40
LCM = 14×40 => 560
TO FIND OTHER NO. :-
first no. = 280
second no. = y
WE KNOW THAT
40 × 560 = 280 × y
22400 = 280y
y = 22400/280
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