Question

The LCM of two numbers is 14 times their HCF the sum of LCM AND HCF is 600 if one number is 280 then find the other number

Answer 1

Hi ,

Let a , b are two numbers and their LCM

is L and HCF is H

a = 280 ,


L = 14H ---( 1 )

L + H = 600 --( 2 )

substitute ( 1 ) in equation ( 2 ) , we get

14H + H = 600

15H = 600

H = 600/15

H = 40

put H = 40 in equation ( 1 ) , we get

L = 14 × 40 = 560


Therefore ,


a = 280 , b = ? , L = 560 , H = 40

we know,

a × b = L × H

280 × b = 560 × 40

b= ( 560 × 40 )/ 280

b = 80

Therefore ,

second number = b = 80

I hope this helps you.

: )

Answer 2

Given =One number=280
Let the HCF of numbers be =x
LCM of the numbers =14x
According to the question
14x+x=600
15x=600
x=600/15
x=40
So, HCF=40
LCM=14×40=560
We knows the formula that is
LCM×HCF=First number×Second number
putting the values
560×40=280×2 number
22400=280×2 number
2 number=22400/280
2 number=80
So, Other number is 80
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST