The LCM of two numbers is 14 times their HCF.the sum of LCM and HCF is 600 if one number is 280 then find the other number
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Let HCF = x
Thus LCM = 14x
Now x + 14x = 600
15x = 600
x=600/15
x= 40
HCF = 40
LCM = 14•40
LCM = = 560
Now by Fundamental Theorem of Arithmetic
Product of two numbers = LCM × HCF
280•No 2 = 560•40
No 2 = 560 × 40 / 280
No 2 = 80
Thus the other no = 80
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Thus LCM = 14x
Now x + 14x = 600
15x = 600
x=600/15
x= 40
HCF = 40
LCM = 14•40
LCM = = 560
Now by Fundamental Theorem of Arithmetic
Product of two numbers = LCM × HCF
280•No 2 = 560•40
No 2 = 560 × 40 / 280
No 2 = 80
Thus the other no = 80
Hope it helps and if it did please Mark as Brainliest
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