Question

the lcm of two numbers is 20 a the hcf is 1 if one number is 4 the other number is​

Answer 1

Answer:

we know that

Step-by-step explanation:

LCM X HCF =A X B

20 x 1 =4 x b

20 = 4 x b

20/4 = b

therefore b = 5

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Answer 2

Answer:

Let 4a & 4b be the two numbers where a & b are co-primes.

Now LCM x HCF = Product of numbers

=> 20 x 4 = 16ab

=> ab = 5

The only possible integer values of a & b is a=1 & b= 5 or a= 5 & b = 1

So, the required numbers are 4 and 20.