the lcm of two numbers is 210 and their hcf is 14 how many such pairs are possible? step by step explanation .
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Step-by-step explanation:
given the LCM of two numbers is 210 and their hcf is 14
supposed two numbers is 14x and 14 y
we know that ,the product of two numbers is = lcm×hcf
thus,14x ×14y =14×210
14xy =210
XY=210\14=30/2=15
therefore,x=1,y=15 and x=3,y=5
hence, (14,210),(42,70)two pairs are possible
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