Question

The lcm of two numbers is 216 and their HCF is 36, If one of the number if 72 find other number.​

Answer 1

Answer:

First, I will find the Prime Factorization for each of the three numbers:

2*2*2*2*3*3 [Prime Factorization of 144]

2*2*2* 3*3*3 [Prime Factorization of 216]

2*2*2*2*3*3*3 [Prime Factorization of 432 (LCM)]

2*2*2* 3*3 [Prime Factorization of 72(HCF)

From this configuration, given that the Prime Factorization of the LCM must have factors that are in one or the other or both of the two numbers and the HCF must have factors that are in both numbers. Therefore, the missing number must have four 2's and two 3's.

2*2*2*2*3*3=144

Answer: 144 is the other number.

Have A Happy Day:-)

Answer 2

Answer:

we know that Lcm× Hcf= 1st no × 2nd no.

Step-by-step explanation:

so 216×36=72× other no. ,other no.=216×36/72=108