Question

The LCM of two numbers is 24 and their HCF is 4. Which of these can be true if the two numbers are denoted by n1 and n2?
   A.  n1 + n2 = 28
   B.  n1 + n2 = 20

Only A Only B Both A and B Neither A nor B​

Answer 1

Answer:

BOTH A and B ARE CORRECT

Step-by-step explanation:

let the two numbers be 4a and 4b where a and b are co prime numbers,

now, H.C.F×L.C.M = two numbers

4 × 24 = 4a × 4b

96 = 4a × 4b

ab = 6

after factorising them ,

(a,b)=(1,6)and (2,3)

so, the possible pair could be

( 4,24 )and ( 8,12 )

according to the question,

4 +24 = 28

8 + 12= 20

hence , both a and b are correct

hope it helps you

thank you

Answer 2

BOTH A and B ARE CORRECT

Step-by-step explanation:

let the two numbers be 4a and 4b where a and b are co prime numbers,

now, H.C.F×L.C.M = two numbers

4 × 24 = 4a × 4b

96 = 4a × 4b

ab = 6

after factorising them ,

(a,b)=(1,6)and (2,3)

so, the possible pair could be

( 4,24 )and ( 8,12 )

according to the question,

4 +24 = 28

8 + 12= 20

hence , both a and b are correct