The lcm of two numbers is 280 and their hcf is 8. If the sum of the number is 96 then the difference is
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let one no. be 'x'and the other no. be 'y'.
LCM*HCF=product of the two no.s
280*8=x*y
2240=xy ____(ii)
we know,
x+y=96
x=96-y ____(i)
substituting (i) in (ii),
=>(96-y)y=2240
96y-y^2=2240
=>y^2-96y+2240=0
y^2-56y-40y+2240=0
y(y-56)-40(y-56)=0
(y-40)(y-56)=0
=>y=40(or)56
if y=40,
x+40=96
x=96-40
=56
if y=56,
x+56=96
x=96-56
=40
therefore the two no.s are 56 and 40.
the difference between the two no.s,
=>56-40=16
LCM*HCF=product of the two no.s
280*8=x*y
2240=xy ____(ii)
we know,
x+y=96
x=96-y ____(i)
substituting (i) in (ii),
=>(96-y)y=2240
96y-y^2=2240
=>y^2-96y+2240=0
y^2-56y-40y+2240=0
y(y-56)-40(y-56)=0
(y-40)(y-56)=0
=>y=40(or)56
if y=40,
x+40=96
x=96-40
=56
if y=56,
x+56=96
x=96-56
=40
therefore the two no.s are 56 and 40.
the difference between the two no.s,
=>56-40=16
barathbarclays100:
tqq u so much may god bless u life long time
madam can you please help me for this sum what is the remainder when 9896319×10^9 is divided by 24?
ur welcome dear....
madam please explain this what is the remainder when 9896319×10^9 is divided by 24?
9896319*10^9/2=3298773*5^3*10^6
madam I can't understand can you please explain fully
=412346625*10^6
yaar.. .its just a normal division which I have done...
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