Question

The LCM of two numbers is 4 times HCF. If the sum of LCM and HCF is 45, and one of the numbers is 9, then find the sum of the squares of those numbers.

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given :   The LCM of two numbers is 4 times HCF. If the sum of LCM and HCF is 45, and one of the numbers is 9

To find : sum of the squares of those numbers.

Solution:

Let say HCF = H

Then LCM = 4 * HCF = 4 H

Sum of LCM & HCF = 45

=> 4H + H = 45

=> 5H = 45

=> H = 9

=> HCF = 9

LCM = 4*9 = 36

LCM * HCF = one number * 2nd number

=> 36 * 9  =  9 * 2nd number

=> 2nd number = 36

Numbers are 9  & 36

sum of the squares of those numbers.

= 9² + 36²

= 9² (1  + 4²)

= 81(1 + 16)

= 81 (17)

= 1377

sum of the squares of those numbers. = 1377

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