Question

the LCM of two numbers is 4 times the sum of LCM and HCF is 45 and one of the number is 9 then find the sum of the squares of the numbers​

Answer 1

Answer:

Step-by-step explanation:

1296

Step-by-step explanation:

Let the HCF=y

LCM=4y

Given LCM+HCF=45

4y+y=45

5y=45

y=9

HCF=9,LCM=36

Ok now save this info,

LCM×HCF=Product of numbers

36×9=9×b(where b is the unknown number)

clearly, b=36

sum of squares=36^2+9^2=1296