The lcm of two numbers .is 45 and their hcf is 5. How many such pairs of numbers are possible
Answers
Answer:
the numbers are 5 and 45
Step-by-step explanation:
We should know that,
Product of the 2 numbers = LCM × HCF
(This is mathematically proven)
So, LCM = 45 and HCF = 5
Now, let the numbers be 5a and 5b where a and b are coprimes
(Coprimes means there are no other common factors between a and b)
Now, I said 5a and 5b because, now a and b are coprimes and if we take the HCF of a and b we get
HCF = 1
But we need HCF = 5
so, the numbers are 5a and 5b
so, 5a × 5b = 45 × 5
25ab = 225
ab = 225/25 = 9
ab = 9
Now, the coprimes pairs which satisfy ab = 9 is (1, 9)
where a = 1
b = 9
See we can't take (3,3) because they have a common factor of 3, we said a and b are coprimes
So, the possible number is 5(1) and 5(9) = 5 and 45
So the numbers are 5 and 45
Answer:
We should know that,
Product of the 2 numbers = LCM × HCF
(This is mathematically proven)
So, LCM = 45 and HCF = 5
Now, let the numbers be 5a and 5b where a and b are coprimes
(Coprimes means there are no other common factors between a and b)
Now, I said 5a and 5b because, now a and b are coprimes and if we take the HCF of a and b we get
HCF = 1
But we need HCF = 5
so, the numbers are 5a and 5b
so, 5a × 5b = 45 × 5
25ab = 225
ab = 225/25 = 9
ab = 9
Now, the coprimes pairs which satisfy ab = 9 is (1, 9)
where a = 1
b = 9
See we can't take (3,3) because they have a common factor of 3, we said a and b are coprimes
So, the possible number is 5(1) and 5(9) = 5 and 45
So, the numbers are 5 and 45
And one and only one pair is possible
Hope it helped and you understood it........All the best
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