Question

the lcm of two numbers is 45 and their hcf is 5 how many such paits are possible​

Answer 1

Answer:

Step-by-step explanation:

let the numbers be 5a and 5b

so

lcm x hcf = 5a x 5b

45 x 5 = 25ab

ab = 9

Either, a = 1 and b= 9 or a=9 and b=1

Their is only one pair.