Question

the lcm of two numbers is 567 and their hcf is 9 if the difference the two numbers is 18 find the two numbers

Answer 1

answer is : a=81 and b=63

use LCM*HCF=a*b

where a and b are the two nos.

By this u will arrive to an eqn b^2+18b-5103=0

Solve this equation

b is obtained as either -81 or 63

ignore the -ve value.

using the +ve value of b we arrive at a. (using |a-b| = 18)

Answer 2

Answer:

63 and 81

Step-by-step explanation:

Productoftwonumber=LCM×HCF

⇒567×9=5103

Let the number are x and x+18

thenx(x+18)=5103

x  

2

+18x−5103=0

x  

2

+81x−63x−5103=0

x(x+81)−63(x+81)=0

(x+81)(x−63)=0

The number are 63 and 81