Question

the LCM of two numbers is 816 and their HCF is 3. If one of the number is 48, find the other.​

Answer 1

WE KNOW THAT LCM × HCF = PRODUCT OF TWO NUMBERS

GIVEN

LCM = 816

HCF = 3

ONE NUMBER = 48

LET OTHER NUMBER BE 'X'

LCM × HCF = PRODUCT OF TWO NUMBERS

816 × 3 = 48 × X

2448 = 48X

X = 2448/48

X = 51

HENCE , THE OTHER NUMBER IS 51.

PLEASE MARK THIS AS THE BRAINLIEST ANSWER

Answer 2

Answer:

We know that H.C.F×L.C.M=product of the numbers.

Let the number be x

⇒ x = LCM × HCF

⇒ 816 × 3 = 48 × x

⇒ 24x = 3 × 316 = 17 × 3

∴ x = 51

Verfication

Lcm of 51 and 48 = 816

Hcf of 51 and 48 = 3

⇒ 816 ×