The LCM of two numbers is45 and there HCF is 5 how many such pairs of numbers are possible
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2
Answer:
8
Step-by-step explanation:
Product of 2 number = HCF x LCM
= 5 x 45
= 225
So, 225 can be made as
1 x 225
3 x 75
5 x 45
15 x 15
15 x 15
45 x 5
75 x 3
225 x 1
Hence, there will be 8 possible conditions.
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