Question

the lcm of two numbes is 2079 and their hcf is 27 if the first number is 189 find the second number​

Answer 1

$\: \: \: \: \: \: \tt{L.C.M \: of \: two \: is \: \red{2079} \: and} \\ \: \: \: \: \: \: \tt{ their \: H.C. F \: is \: \red{27}.}$

$\\ \: \: \: \: \: \: \tt{Let \: the \: first \: n o \: be \: N_1 } \\ </p><p></p><p> \: \: \: \: \: \: \tt{and \: Second \: no \: be \: N_2}$

$\\ \tt \blue{A/Q}$

$\tt{( \pink{H.C.F} \times \pink{L.C.M}) \: of \: two \: no \: = Product \: of \: two \: no.}$

$\tt{Where \: as , }</p><p></p><p> \\ \: \: \: \: \: \: \tt{H.C.F = 27.}</p><p></p><p> \\ \: \: \: \: \: \: \tt{L.C.M = 2079.}</p><p></p><p> \\ \: \: \: \: \: \: \tt{and \: One \: no \: be \: 189.}$

$\: \: \: \: \: \: \tt{27 \times 2079= N_1 \times N_2}$

$\: \: \: \: \: \: \tt{27 \times 2079 = 189 \times N_2}$

$\: \: \: \: \: \: \tt{\frac{27 \times 2079}{189} = N_2}$

$\: \: \: \: \: \: \tt{N_2 = 297.}$