Question

the LCM of x ²-16 and 2x²-9 x+4 is
a) (2x+1) (x+4) (x-4)
b) (x²+16) (2x+1)
c) 2(1-2x) (x+ 4) (x-4 )
d) (2x-1) (x+4) (x-4) ​

Answer 1

Answer:

LCM = (x-4)(x+4)(2x-1)

Step-by-step explanation:

${x}^{2} - 16 = {x }^{2} - {4}^{2} = (x - 4)( x+ 4)$

Similarly factorize

$2 {x}^{2} - 9x + 4 = 2 {x}^{2} - 8x - x + 4 \\ \implies \: = (x - 4)(2x - 1)$

LCM = (x-4)(x+4)(2x-1)