Question

The LCM of (x+y)² , (x-y)² and (x²-y²) is​

Answer 1

Step-by-step explanation:

(x+y)²=(x+y)(x+y)

(x-y)²=(x-y)(x-y)

x²-y²=(x-y)(x+y)

so LCM =(x+y)²(x-y)².(Answer)

hope it will help you.