the lcm of x²-1,x²+x,(x+1)²????
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Answer:
x(x-1)(x+1)(x+1)
Step-by-step explanation:
Find lcm of x²-1,x²+x,(x+1)²
Factorizing the given:
- x²-1=x(x-1)
- x²+x=x(x+1)
- (x+1)= (x+1)(x+1)
Finding LCM:
LCM= x(x-1)(x+1)(x+1)
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