Math, asked by roxykennedy3129, 10 months ago

The lcm of x3-a3 and (x-a) 2 is

Answers

Answered by Ahadbeg
5

Answer:

Step-by-step explanation:

L C M of (x³-a³) and 2(x-a) = ( x-a) ×(x²-a²) ×2

                                            = 2(x³+a³-a²x-ax²)

so,

    LCM oF x³-a³  and 2(x-a) is 2(x³+a³-a²x-ax²)

Answered by mahitiwari89
5

Use formula of (x^{3}-a^{3}) = (x-a)(x^{2}+xa+a^{2})

Step-by-step explanation:

(x^{3}-a^{3}) = (x-a)(x^{2}+xa+a^{2})

(x-a)^{2} = (x-a)(x-a)

LCM of (x^{3}-a^{3}) and(x-a)^{2} = (x-a)^{2}(x^{2}+xa+a^{2})

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