Physics, asked by arjuja123, 8 months ago

the LCR circuit R=3ohm, XL=8 ohm, Xc= 4 ohm, the impedance of the circuit is​

Answers

Answered by 1320
11

Answer

Z=√(xl-xc)2 +R2

Z=√(8square-4square)2+3square

Z=√16+9

Z=√25

Z=5

Explanation:

Answered by muscardinus
4

The impedance of the circuit is​ 5 ohms.

Explanation:

Given that,

Resistance, R = 3 ohms

Inductive reactance, X_L=8\ \Omega

Capacitive reactance, X_C=4\ \Omega

We need to find the impedance of the circuit. In a series LCR circuit, the impedance of circuit is given by :

Z=\sqrt{R^2+(X_L-X_C)^2}

Z=\sqrt{(3)^2+(8-4)^2}

Z = 5 ohms

So, the impedance of the circuit is​ 5 ohms. Hence, this is the required solution.

Learn more,

LCR circuit

https://brainly.in/question/5409775

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