Question

The leading coefficient of a polynomial P(x) of

degree 3 is 2006. Suppose that P(1) = 5, P(2) = 7

and P(3) = 9, then find P(x).

(1) 2006 (x–1) (x–2) (x– 3) + 2x + 3

(2) 2006 (x–1) (x–2) (x– 3) + 2x + 1

(3) 2006 (x–1) (x–2) (x– 3) + 2x – 1

(4) 2006 (x–2) (x–3) (x– 1) –( 2x – 3)

Answer 1

i hope the answer is 2)2006 (x-1)(x-2)(x-3)+2x+1