The leading coefficient of a polynomial PX of degree 3 is 2006 supposed that p 1 is equal to 5 p 2 equal to 7 and P3 equal to 9 then find PX
Answers
Answered by
15
Let,
P(x)=2006x^3+bx^2+cx+d
P(1)=2006+b+c+d=5
2001+b+c+d=0------(1)
P(2)=2006×8+4b+2c+d=7
16041+4b+2c+d=0------(2)
P(3)=2006×27+9b+3c+d=9
54153+9b+3c+d=0------(3)
We have 3 equations and 3 variables b,c,d
By solving we get
b=-12036
c=-22068
d=-12033
P(x)=2006x^3-12036x^2-22068x-12033
P(x)=2006x^3+bx^2+cx+d
P(1)=2006+b+c+d=5
2001+b+c+d=0------(1)
P(2)=2006×8+4b+2c+d=7
16041+4b+2c+d=0------(2)
P(3)=2006×27+9b+3c+d=9
54153+9b+3c+d=0------(3)
We have 3 equations and 3 variables b,c,d
By solving we get
b=-12036
c=-22068
d=-12033
P(x)=2006x^3-12036x^2-22068x-12033
Answered by
3
Answer:
2006(x-1) (x-2) (x-3) +2x+3
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