Question

the leanght of the diagonals of the rombus are 24 cm and 32 cm . find the length of its sides​

Answer 1

Answer:

1st diagonal is 24cm

half of the diagonal is 12cm

2nd diagonal is 32cm

half of the diagonal is 16cm

Apply pythagoras theorem for 12 and 16cm

12^2 + 16^2 = 144 + 256

400

side = root 400

20

Answer 2

Step-by-step explanation:

let AC= 24cm and BD= 32cm

so, AO=½AC= ½×24= 12cm

OD=½BD=½×32= 16cm

In triangle AOD,

AD²=AO²+OD²

AD²=(12)²+(16)²

AD²=144+256

AD²=400

AD= 20cm

so, AD=AB=BC=CD=20cm

therefore the length of sides of rhombus is 20cm

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